Multiple choice

Passage

Read the following information carefully to answer the questions asked- There are three persons in a family A, B and C. A's age is 3 years more than B's age. B's age is 4 times of C's age. They have celebrated their birthday in the different ratio A's birthday celebration is 500% of C’s birthday celebration and B's birthday celebration is 0.7 times of A's birthday celebration. Note-This is not necessary that every year birthday is celebrated by A, B and C.

3years ago difference between the average age of A, B and F with the average age of C, D and F was 10 years. Then find the ratio between the age of F and D.

  1. 1:5

  2. 2:5

  3. 1:1

  4. 8:5

  5. None of these
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

3 years ago, average of (A, B, F) minus average of (C, D, F) = 10. This gives (A+B+F)/3 - (C+D+F)/3 = 10, or (A+B-C-D)/3 = 10, so A+B-C-D = 30. Without additional information about individual ages or relationships, we cannot determine the specific ratio of F:D. The question is under-specified.

Keep practicing — related questions