Multiple choice

Passage

Read the following information carefully to answer the questions asked- There are three persons in a family A, B and C. A's age is 3 years more than B's age. B's age is 4 times of C's age. They have celebrated their birthday in the different ratio A's birthday celebration is 500% of C’s birthday celebration and B's birthday celebration is 0.7 times of A's birthday celebration. Note-This is not necessary that every year birthday is celebrated by A, B and C.

Ratio of age of C and D is in the ratio of 2:5 and E and D in the ratio of 4:5. If E age is 6 years more than C. Then find the age of E?

  1. 12

  2. 18

  3. 9

  4. 15

  5. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Given C:D = 2:5 and E:D = 4:5, so C:D:E = 2:5:4. Let common ratio be x, so C=2x, D=5x, E=4x. Given E is 6 years more than C: 4x = 2x + 6, so 2x = 6, x = 3. Therefore E = 4 × 3 = 12 years. Option A (12) is correct.

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