Multiple choice

In an examination, Akashi's average marks were 57 per paper. If he had obtained 18 more marks in his English paper and 4 more marks in his Mathematics paper, his average per paper would have been 59. How many more papers except English and Mathematics were there in the examination?

  1. 5

  2. 9

  3. 11

  4. 13
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B Correct answer
Explanation

Let n be the total number of papers. Total marks = 57n. New total = 57n + 18 + 4 = 57n + 22. New average = 59 = (57n + 22) / n. 59n = 57n + 22 => 2n = 22 => n = 11. Total papers = 11. Excluding English and Math, there are 11 - 2 = 9 papers.

AI explanation

The total increase in marks is 18 plus 4, which equals 22. This total increase raises the overall average by 2 points, from 57 to 59. Let the total number of papers be x; then 22 divided by x equals 2, meaning x is 11. Excluding the English and Mathematics papers, the number of remaining papers is 11 minus 2, which is 9.

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