Multiple choice

Directions: In the following question, equations (i) and (ii) are given. You have to solve both the equations and give answer accordingly. (i) 56x2 + 30x + 4 = 0 (ii) 64y2 + 28y + 3 = 0

  1. x ≥ y

  2. x < y

  3. x ≤ y

  4. x > y

  5. x = y or no relation can be established between x and y
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

For 56x^2 + 30x + 4 = 0, roots are negative. For 64y^2 + 28y + 3 = 0, roots are negative. Solving for x: x = (-30 +/- sqrt(900 - 896))/112 = (-30 +/- 2)/112. Roots are -28/112 = -0.25 and -32/112 = -0.285. For y: y = (-28 +/- sqrt(784 - 768))/128 = (-28 +/- 4)/128. Roots are -24/128 = -0.1875 and -32/128 = -0.25. Comparing values, x <= y.

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