Solve x + y = x2 - y2 = 23 and find the value of y.
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Solve x + y = x2 - y2 = 23 and find the value of y.
11
12
24
36
x + y = 23. x^2 - y^2 = (x+y)(x-y) = 23. Since x+y = 23, then 23(x-y) = 23, so x-y = 1. We have x+y=23 and x-y=1. Adding them: 2x = 24 => x=12. Subtracting: 2y = 22 => y=11.
Using the difference of squares formula on x^2 - y^2 = 23 gives (x - y)(x + y) = 23. Substituting x + y = 23 into this yields (x - y)(23) = 23, meaning x - y = 1. Solving the system x + y = 23 and x - y = 1 gives 2x = 24, so x = 12, and substituting x back gives y = 11.