Multiple choice

A train covers 3584 km in 2 days 8 hours. If it covers 1440 km on the first day and 1608 km on the second day, by how much does the average speed of the train for the remaining part of the journey differ from that for the entire journey?

  1. 3 km/hour more

  2. 3 km/hour less

  3. 4 km/hour more

  4. 5 km/hour less

  5. 4 km/hour less
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Total distance = 3584 km, Total time = 56 hours. Average speed = 3584/56 = 64 km/h. Remaining distance = 3584 - 1440 - 1608 = 536 km. Remaining time = 56 - 24 - 24 = 8 hours. Remaining speed = 536/8 = 67 km/h. Difference = 67 - 64 = 3 km/h more.

AI explanation

The train covers 3584 km in 2 days 8 hours, which is 56 hours, making its overall average speed 3584 divided by 56, equaling 64 km/hr. The remaining distance is 3584 minus 1440 minus 1608, leaving 536 km to be covered in the remaining 8 hours. The average speed for this remaining part is 536 divided by 8, equaling 67 km/hr, which is 3 km/hr more than the overall average speed.

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