Directions: Solve the equations given below and choose the correct option. I. x2 + 4x + 4 = 0 II. y2 - 8y + 16 = 0
Reveal answer
Fill a bubble to check yourself
Directions: Solve the equations given below and choose the correct option. I. x2 + 4x + 4 = 0 II. y2 - 8y + 16 = 0
x ≥ y
x > y
x ≤ y
x < y
x = y or no relation can be established between x and y
Equation I: x^2 + 4x + 4 = 0 implies (x+2)^2 = 0, so x = -2. Equation II: y^2 - 8y + 16 = 0 implies (y-4)^2 = 0, so y = 4. Since -2 < 4, x < y.
The first equation x squared plus 4x plus 4 equals zero is a perfect square trinomial, yielding the repeated root x equals negative 2. The second equation y squared minus 8y plus 16 equals zero is also a perfect square trinomial, yielding the repeated root y equals 4. Comparing these distinct roots, negative 2 is strictly less than 4, establishing that x is less than y.