Multiple choice

Directions: In the given question, equations numbered I and II are given. Solve both equations and give answer. I. (x2 - 5x + 3) + (6x + 3 - 2x2) = 0 II. (2y2 - 11y + 5) - (y2 - 19y - 7) = 0

  1. x > y

  2. x ≤ y

  3. x ≥ y

  4. x < y

  5. x = y or relation between x and y cannot be established
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

I: x^2 - 5x + 3 + 6x + 3 - 2x^2 = 0 => -x^2 + x + 6 = 0 => x^2 - x - 6 = 0 => (x-3)(x+2) = 0, so x = 3, -2. II: 2y^2 - 11y + 5 - y^2 + 19y + 7 = 0 => y^2 + 8y + 12 = 0 => (y+6)(y+2) = 0, so y = -6, -2. Comparing x={3, -2} and y={-6, -2}, x >= y.

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