To start a new enterprise, Mr. Yogesh had borrowed a total of Rs. 60,000 from two moneylenders with the interest being compounded annually to be repaid at the end of two years. Mr. Yogesh repaid Rs. 38,800 more to the first moneylender compared to the second moneylender at the end of two years. The first moneylender charged an interest rate, which was 10% more than what was charged by the second moneylender. If Mr. Yogesh had instead borrowed Rs. 30,000 from each at their respective initial rates for two years, then he would have paid Rs. 7500 more to the first moneylender as compared to the second. The money borrowed by Mr. Yogesh from the first moneylender is (approx.)

Let the principal borrowed from the first moneylender be x at an interest rate of r, making the second principal (60000 - x) at a rate of (r - 10). The second condition states that if Rs. 30,000 is borrowed from each, the difference in amounts after two years is Rs. 7500, giving the equation 30000(1 + r/100)^2 - 30000(1 + (r - 10)/100)^2 = 7500. Simplifying this equation by taking 30000 common and dividing 7500 by it results in (1 + r/100)^2 - (r/90)^2 = 0.25. Using the difference of squares a^2 - b^2 = (a - b)(a + b), we get (100r + 9000 - r^2)/9000 * (100r + 9000 + r^2)/9000 = 0.25. Solving this quadratic relationship yields an interest rate r of 50%. Applying this 50% rate to the first condition where the first repayment was Rs. 38,800 more than the second, we set up x(1.5)^2 - (60000 - x)(1.4)^2 = 38800, which simplifies to 2.25x - 117600 + 1.96x = 38800. Combining like terms gives 4.21x = 156400, and solving for x results in Rs. 37,152, which is approximately Rs. 40,000.

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