Multiple choice

Car A leaves City H at 3:00 PM and drives toward City J at a constant speed of 72 kilometers per hour. Car B leaves City H later the same day toward City J at its own constant speed. At what time will Car B catch up to Car A? (1) Car B leaves City H at 4:30 PM. (2) Car A's speed is 4 5 of Car B's speed.

  1. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

  2. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

  3. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

  4. EACH statement ALONE is sufficient.

  5. Statements (1) and (2) TOGETHER are NOT sufficient.
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Statement 1 gives the start time for Car B. Statement 2 gives the ratio of speeds. To find when Car B catches Car A, we need both the relative start time and the relative speed to determine the distance gap and the rate at which it closes.

AI explanation

Statement one gives the time delay between the two cars but lacks any information about their relative speeds, making it impossible to find the catch up time. Statement two provides the ratio of their speeds, stating Car A travels at 4/5 of Car B's speed, but without the actual time delay we cannot find the catch up time. Using both statements together, the 1.5 hour head start means Car A travels 108 km, and since Car B travels 1/4 faster, it closes this 108 km gap at a relative catch up rate, allowing us to calculate the exact meeting time.

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