Multiple choice

Quantity I: A bus travels a distance 60km at the speed of 30kmph. It covers the next 15km of its journey at the speed of 5kmph and the last 60km of its journey at the speed of 20kmph. Find the average speed of the bus. Quantity II: A car covers a distance of 240km in a certain amount of time at speed of 30 kmph. What is the average speed of bike that covers distance of 30km less than that of the car in 2 hours less than time taken by car?

  1. Quantity I > Quantity II

  2. Quantity I ≥ Quantity II

  3. Quantity II > Quantity I

  4. Quantity II ≥ Quantity I

  5. Quantity I = Quantity II or Relation cannot be established
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Quantity I: Total distance = 60+15+60 = 135 km. Total time = 60/30 + 15/5 + 60/20 = 2 + 3 + 3 = 8 hours. Avg speed = 135/8 = 16.875 kmph. Quantity II: Car time = 240/30 = 8 hours. Bike distance = 240-30 = 210 km. Bike time = 8-2 = 6 hours. Avg speed = 210/6 = 35 kmph. Quantity II > Quantity I.

AI explanation

For Quantity I, the average speed of the bus is total distance divided by total time; the total distance is 60 plus 15 plus 60, equaling 135 km. The total time is (60/30) plus (15/5) plus (60/20), which simplifies to 2 plus 3 plus 3, equaling 8 hours, making the average speed 135 divided by 8, or 16.875 km/hr. For Quantity II, the car travels 240 km at 30 km/hr, taking 8 hours, so the bike travels 30 km less, or 210 km, in 2 hours less, which is 6 hours. The bike's average speed is 210 divided by 6, equaling 35 km/hr. Comparing the two values, 35 is greater than 16.875, so Quantity II is greater than Quantity I.

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