Multiple choice

Two brothers, David and Joseph, started traveling to their aunt Sophia's town. Both decided to go separately using different means of transportation. David decided to travel through a train and Joseph through a car. The speed of the train was 50% more than that of the car. Joseph and David both first arrived at the railway station. David then moved to his train. Then, both started from there together at the same time and reached their aunt's place, which was 75 miles away, at the same time. On the way, the train lost 15 minutes while stopping at stations. What was the speed of the car?

  1. 125 miles per hour

  2. 120 miles per hour

  3. 110 miles per hour

  4. 100 miles per hour

  5. 95 miles per hour
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let car speed be v. Train speed = 1.5v. Time for car = 75/v. Time for train = 75/(1.5v) + 15/60 = 50/v + 0.25. Since they arrive together: 75/v = 50/v + 0.25 -> 25/v = 0.25 -> v = 100.

AI explanation

Let the speed of the car be v miles per hour, making the train's speed 1.5v. The time taken by the car is 75 divided by v, and the time taken by the train is 75 divided by 1.5v plus 0.25 hours for the delay. Equating the two times gives 75 divided by v equals 50 divided by v plus 0.25. Solving this equation results in 25 divided by v equals 0.25, so v equals 100 miles per hour.

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