Multiple choice

Each question below contains a statement followed by Quantity I and Quantity II. Find both to find the relationship among them. Mark your answer accordingly. Quantity I: The ratio of the present age of Prem and Pravin is 8:7. After 10 years the ratio of Prem and his son is 3:1. Sum of the present age of Prem and his son's age after 4 years is 40 years. Then find the Pravin's present age? Quantity II: The present age of mother is two years less than thrice the age of her daughter. After two years the mother's age will be 10 years more than twice the age of her daughter. What is the present age of mother?

  1. Quantity I > Quantity II

  2. Quantity II > Quantity I

  3. Quantity I ≥ Quantity II

  4. Quantity II ≥ Quantity I

  5. Quantity I = Quantity II or Relation cannot beestablished
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Quantity I: Prem/Pravin = 8x/7x. Prem+10 / (Son+10) = 3/1. Prem + (Son+4) = 40. Solving these yields Pravin's age as 21. Quantity II: M = 3D - 2. (M+2) = 2(D+2) + 10. Solving yields M = 25. Since 25 > 21, Quantity II > Quantity I.

AI explanation

For Quantity I, let the ratio of present ages of Prem and his son after 10 years be 3x and 1x; the son's present age is x minus 10. Given Prem's present age plus the son's age after 4 years equals 40, and using the 8:7 ratio for Prem's present age, Prem's son's present age is 5 and Prem is 28, making Pravin 28 divided by 8 times 7 equal to 24.5 years. For Quantity II, let the daughter's present age be d, making the mother 3d minus 2; after two years, 3d minus 2 plus 2 equals 10 plus 2 times d plus 2, which gives the mother's age as 34 years. Since 34 is greater than 24.5, Quantity II > Quantity I.

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