Equation of (x+1)2-x2 = 0 has number of real roots equal to:
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Equation of (x+1)2-x2 = 0 has number of real roots equal to:
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(x+1)^2 - x^2 = 0 expands to x^2 + 2x + 1 - x^2 = 0, which simplifies to 2x + 1 = 0. This linear equation has exactly one real root, x = -1/2.
Expand the binomial to get x^2 + 2x + 1 - x^2 = 0. This simplifies to the linear equation 2x + 1 = 0, which has the single real root x = -1/2. The equation has exactly 1 real root.