What is the sum of the square of the roots of the equation p² - 13p + 9 = 0 ?
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What is the sum of the square of the roots of the equation p² - 13p + 9 = 0 ?
169
162
151
154
144
For p^2 - 13p + 9 = 0, sum of roots (r1+r2) = 13, product (r1*r2) = 9. Sum of squares = r1^2 + r2^2 = (r1+r2)^2 - 2(r1*r2) = 13^2 - 2(9) = 169 - 18 = 151.
Using the relationship between roots and coefficients for the equation p squared minus 13p plus 9 equals zero, the sum of the roots is 13 and the product is 9. The sum of the squares of the roots is found using the identity sum squared minus twice the product. Substituting the values gives 169 minus 18, which equals 151.