Multiple choice

Directions: In the following question, two equations (i) and (ii) are given, you have to solve both the equations and give answer accordingly. (i) 3x2 + 13x + 14 = 0 (ii) 5y2 + 18y + 9 = 0

  1. x ≥ y

  2. x < y

  3. x ≤ y

  4. x = y or no relation can be established between x & y.

  5. x > y
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

(i) 3x^2 + 13x + 14 = 0 -> (3x + 7)(x + 2) = 0 -> x = -7/3, -2. (ii) 5y^2 + 18y + 9 = 0 -> (5y + 3)(y + 3) = 0 -> y = -3/5, -3. Comparing values: -2.33, -2 vs -0.6, -3. Since -2 > -3 and -2 < -0.6, no relation can be established.

AI explanation

Solving the first quadratic equation 3x squared plus 13x plus 14 equals 0 by factorization gives (x plus 2)(3x plus 7) equals 0, so x equals minus 2 or minus 2.33. Solving the second equation 5y squared plus 18y plus 9 equals 0 gives (y plus 3)(5y plus 3) equals 0, so y equals minus 3 or minus 0.6. Since the lowest value of x is minus 2.33 which is greater than y equals minus 3, but the highest value of x is minus 2 which is less than y equals minus 0.6, no relation can be established between x and y.

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