What is the number of real roots of the equation (x - 1)2 + (x - 3)2 + (x - 5)2 = 0?
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What is the number of real roots of the equation (x - 1)2 + (x - 3)2 + (x - 5)2 = 0?
None
Only one
Only two
Three
A sum of squares equals zero if and only if each term is zero. (x-1)^2=0, (x-3)^2=0, (x-5)^2=0. This implies x=1, x=3, and x=5 simultaneously, which is impossible. Thus, there are no real roots.
The equation consists of three squared terms summing to zero. Because the square of any real number cannot be negative, the only way for their sum to be zero is if each term is individually equal to zero. Setting the terms to zero requires x to equal 1, 3, and 5 simultaneously, which is impossible for a single real number. Therefore, the equation has no real roots.