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Multiple choice

The number of real roots of the equation e4x + 2e3x - ex - 6 = 0 is:

  1. 0

  2. 1

  3. 4

  4. 2

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let y = e^x. The equation becomes y^4 + 2y^3 - y - 6 = 0. Testing roots, y = 1.35 approx is the only positive root (since e^x > 0). Thus, there is only one real root for x.

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