Multiple choice The number of real roots of the equation e4x + 2e3x - ex - 6 = 0 is: 0 1 4 2 Reveal answer Fill a bubble to check yourself B Correct answer Explanation Let y = e^x. The equation becomes y^4 + 2y^3 - y - 6 = 0. Testing roots, y = 1.35 approx is the only positive root (since e^x > 0). Thus, there is only one real root for x.