If roots of the equation lx^2 + mx - 2 = 0 are reciprocal of each other, then
Reveal answer
Fill a bubble to check yourself
If roots of the equation lx^2 + mx - 2 = 0 are reciprocal of each other, then
l = 2
l=-2
m = 2
m = - 2
If roots are reciprocals, their product is 1. For lx^2 + mx - 2 = 0, the product of roots is c/a = -2/l. Setting -2/l = 1 gives l = -2.
For a quadratic equation lx squared plus mx minus 2 equals 0, the product of the roots is given by the constant term divided by the leading coefficient, which is negative 2 divided by l. Since the roots are reciprocals of each other, their product must equal 1. Setting negative 2 divided by l equal to 1 gives l equals negative 2.