If the roots of the equations 6x2 – 7x + k = 0 are rational. The k is equal to
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If the roots of the equations 6x2 – 7x + k = 0 are rational. The k is equal to
–1
–1, –2
–2
1, 2
For roots to be rational, the discriminant D = b^2 - 4ac must be a perfect square. D = (-7)^2 - 4(6)(k) = 49 - 24k. For 49 - 24k to be a perfect square, testing k=1 gives 25 (square), testing k=2 gives 1 (square).
For the quadratic equation to have rational roots, its discriminant must be a perfect square. The discriminant is (-7)^2 - 4(6)(k) = 49 - 24k. Testing the provided pairs for k, if k = 1, the discriminant is 25; and if k = 2, the discriminant is 1, both of which are perfect squares.