If α and β are the zeros of the quadratic polynomial 2x2 + 7x + 5, what is the value of ( 1 α + 1 β ) ?
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If α and β are the zeros of the quadratic polynomial 2x2 + 7x + 5, what is the value of ( 1 α + 1 β ) ?
7 5
5 7
− 7 5
− 5 7
For 2x^2 + 7x + 5, sum of roots (alpha + beta) = -7/2 and product (alpha * beta) = 5/2. The expression (1/alpha + 1/beta) = (alpha + beta) / (alpha * beta) = (-7/2) / (5/2) = -7/5.
For the quadratic polynomial 2x squared plus 7x plus 5, the sum of the roots (alpha plus beta) is negative 7 divided by 2, and the product (alpha beta) is 5 divided by 2. The expression (1 divided by alpha plus 1 divided by beta) simplifies to (alpha plus beta) divided by (alpha beta). Substituting the values gives (negative 7 divided by 2) divided by (5 divided by 2), which equals negative 7 divided by 5.