While solving the quadratic equation 2x² + 8x - 56 = 8, what is the value that should be added on left side of equation to complete the square?

First, move the constant to the left side to obtain 2x^2 + 8x - 64 = 0. Divide the entire equation by 2 to get x^2 + 4x - 32 = 0, and then move the constant term to the right side, yielding x^2 + 4x = 32. To complete the square using the identity (a + b)^2 = a^2 + 2ab + b^2, we take half of the x coefficient (4/2 = 2) and square it to get 4. Adding this 4 to the left side completes the square.

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