Which of the following quadratic equations has a solution 3 and -2?
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Which of the following quadratic equations has a solution 3 and -2?
x2 - 2x + 6 = 0
x2 + x - 6 = 0
x2 - 3x + 6 = 0
x2 - x - 6 = 0
If the roots are 3 and -2, the equation is (x - 3)(x + 2) = 0, which expands to x^2 - x - 6 = 0.
Using the sum and product of roots method, a quadratic equation can be written as x squared minus (sum of roots)x plus (product of roots) equals 0. For the roots 3 and -2, the sum is 1 and the product is -6. Substituting these values gives x squared minus x minus 6 equals 0.