Which of the following values of x satisfies the quadratic equation x(x - 16) = 132?
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Which of the following values of x satisfies the quadratic equation x(x - 16) = 132?
6
23
2
x^2 - 16x - 132 = 0. Factors of -132 that add to -16 are -22 and 6. (x - 22)(x + 6) = 0. Roots are 22 and -6.
First, expand the given equation x(x - 16) = 132 to get the standard quadratic form x2 - 16x - 132 = 0. Next, factor the quadratic equation by finding two numbers that multiply to -132 and add to -16, which are -22 and 6. This gives the factored form (x - 22)(x + 6) = 0, meaning the roots are x = 22 and x = -6. Therefore, the value that satisfies the equation from the given choices is -6.