Multiple choice

A vessel contains 6 liters of a solution with 10% alcohol and 90% water. If 3 liters of this solution are replaced with pure alcohol, what percentage of the resulting mixture is alcohol?

  1. 35%

  2. 45%

  3. 55%

  4. 60%

  5. 70%
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Initial: 6 liters, 10% alcohol = 0.6L alcohol, 5.4L water. Replace 3 liters of solution: 3 liters removed contains 0.3L alcohol and 2.7L water. Remaining: 0.3L alcohol, 2.7L water. Add 3 liters pure alcohol: Total alcohol = 0.3 + 3 = 3.3L. Total volume = 6L. Percentage = (3.3 / 6) * 100 = 55%.

AI explanation

When 3 liters are removed from 6 liters, 3 liters of the original solution remain, containing 0.3 liters of alcohol. Adding 3 liters of pure alcohol brings the total alcohol to 3.3 liters in a 6 liter mixture. The percentage is (3.3 / 6) * 100, which equals 55%.

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