Multiple choice

A vessel contains 64 liters of milk. 16 liters are removed and replaced by water. This process is repeated two more times (total 3 replacements). Final quantity of milk left (in liters) is:

  1. 27

  2. 28

  3. 30

  4. 32
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A Correct answer
Explanation

Initial milk = 64. After 3 replacements of 16 liters (1/4 of the total), the remaining milk is 64 * (1 - 16/64)^3 = 64 * (3/4)^3 = 64 * 27/64 = 27 liters.

AI explanation

Using the formula for repeated replacement, the final quantity of milk is calculated as Initial Amount multiplied by (1 - Replaced Amount / Total Amount) ^ n. Substituting the given values results in 64 multiplied by (1 - 16 / 64) ^ 3. This simplifies to 64 multiplied by (3/4) ^ 3, which is 64 multiplied by 27/64. The final quantity of milk left is 27 liters.

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