Multiple choice

From a container having pure milk in it, 20% of the milk is first removed and replenished with an equal volume of water and solution A is formed. Then, 40% of solution A is removed and replenished with an equal volume of water and solution B is formed. Finally, 60% of solution B is removed and replenished with an equal volume of water and solution C is formed. Find the ratio of the amount of water in solution A to the amount of milk in solution C.

  1. 5 : 4

  2. 25 : 22

  3. 5 : 3

  4. 25 : 24
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let initial milk = 100. After 20% removal and replacement, milk = 80, water = 20. After 40% removal of solution A, milk = 80*0.6 = 48, water = 20*0.6 = 12. Add 40 water: milk = 48, water = 52. After 60% removal of solution B, milk = 48*0.4 = 19.2, water = 52*0.4 = 20.8. Add 60 water: milk = 19.2, water = 80.8. The ratio of water in A (20) to milk in C (19.2) is 20/19.2 = 200/192 = 25/24.

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