Multiple choice

Two containers A and B have equal quantity of diluted milk. In container A, the concentration of milk is 80% and in container B, it is 60%. If 10% of diluted milk from container A is transferred to B and then 10% of this mixture from B is transferred back to A, what will happen to the concentration of milk in container B?

  1. It increases

  2. It decreases

  3. It doesn`t change

  4. Cannot be determined
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let the initial quantity in each container be 100 units. Container A has 80 units of milk, and B has 60 units. After transferring 10 units from A to B, B now has 110 units of liquid with 60 + 8 = 68 units of milk (concentration 68/110 = 61.8%). When 10% of this mixture (11 units) is transferred back to A, the amount of milk removed from B is 11 * (68/110) = 6.8 units. The remaining milk in B is 68 - 6.8 = 61.2 units in 99 units of liquid, resulting in a concentration of 61.2/99 = 61.8%, which is an increase from the original 60%.

AI explanation

Container B initially has a 60% milk concentration, and container A has an 80% concentration. When 10% of the mixture from A is transferred to B, the higher concentration milk from A enters B. Since B receives a mixture that is richer in milk than its current contents, its overall milk concentration increases.

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