There are three containers I, II and III which contain water, milk and acid respectively in equal quantities. 10% of the content of I is taken out and poured into II. Then, the same amount from II is transferred to III, from which again the same amount is transferred to I. What is the proportion of milk in container I at the end of the process?

Assume each container initially holds 100 units. When 10 units of water are poured from container I into container II, container II holds 100 units of milk and 10 units of water. Transferring 10 units from container II to container III moves 100/11 units of milk. Finally, transferring 10 units from container III to container I moves 1000/121 units of milk into container I. The proportion of milk in container I is 1000/12100, which simplifies to 1 121.

• Thanks
• Wrong explanation