Multiple choice

Bottle A contains 60% milk and the rest is water. Bottle B contains 75% of milk and the rest is water. Some amount of liquid from the first bottle is mixed with twice the same amount of liquid from Bottle B. Find the percentage of milk in the resultant liquid.

  1. 66%

  2. 38%

  3. 71%

  4. 70%

  5. 79%
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D Correct answer
Explanation

Let amount from A be x, from B be 2x. Milk in A = 0.6x. Milk in B = 0.75 * 2x = 1.5x. Total milk = 2.1x. Total volume = 3x. Percentage = 2.1x / 3x = 0.7 = 70%.

AI explanation

Using the weighted average formula, if one part is taken from Bottle A and two parts from Bottle B, the percentage of milk in the resultant liquid is calculated as the sum of each component's concentration multiplied by its proportion. The weighted average equals (1 times 60) plus (2 times 75), all divided by 3. This results in 60 plus 150, giving a total of 210. Dividing 210 by 3 yields a final milk concentration of 70%.

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