In a mixture of milk, water, and honey in the ratio 6 : 10 : 11, 40% of it is removed. After this, the difference between the quantities of milk and honey becomes 24 liters. Later, 34 liters of milk is added to the mixture. What will be the new percentage of water in the mixture?

If 40% of the mixture is removed, 60% of the initial ratio 6:10:11 remains, giving quantities of 3.6x, 6x, and 6.6x for milk, water, and honey respectively. Since the question states the exact difference between milk and honey becomes 24 liters, we solve 6.6x - 3.6x = 24, meaning 3x = 24 and x = 8. The quantities become 28.8 liters of milk, 48 liters of water, and 52.8 liters of honey; adding 34 liters of milk makes the new mixture total 163.6 liters, so the new percentage of water is 48 / 163.6 * 100, which equals 29.33% and is not among the listed options.

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