Multiple choice

Quantity I: A milkman has 45 liters mixture of milk and water in the ratio of 5: 4. If 10 liters water is added, then what is percentage of water in the final mixture? Quantity II: A vessel contains 40 liters mixture of water and acid in the ratio of 3: 2. If 20 liters of mixture is taken out and replaced by water, then what percentage of acid in the final mixture?

  1. Quantity I > Quantity II

  2. Quantity I ≥ Quantity II

  3. Quantity II > Quantity I

  4. Quantity II ≥ Quantity I

  5. Quantity I = Quantity II or Relation cannot be established
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A Correct answer
Explanation

Quantity I: 45L, 5:4 ratio. Milk = 25, Water = 20. Add 10L water: Water = 30, Total = 55. %Water = 30/55 = 54.54%. Quantity II: 40L, 3:2 ratio. Water = 24, Acid = 16. Remove 20L mixture (12 water, 8 acid). Remaining: 12 water, 8 acid. Add 20L water: Total water = 32, Total acid = 8, Total volume = 40. %Acid = 8/40 = 20%. Quantity I > Quantity II.

AI explanation

For Quantity I, the initial mixture has 25 liters of milk and 20 liters of water; adding 10 liters of water gives 30 liters of water out of 55 liters, yielding 54.54%. For Quantity II, the 40 liters initially holds 24 liters of water and 16 liters of acid; replacing 20 liters of mixture with water leaves 8 liters of acid, yielding 20%. Quantity I is greater than Quantity II.

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