A tank contains 6 gallons of lemonade and 3 gallons of water. How many gallons of water must be added to the tank to create a mixture that is 2 parts lemonade to 5 parts water by volume?

The initial mixture contains 6 gallons of lemonade and 3 gallons of water, and the target ratio requires 5 parts water for every 2 parts lemonade. Since the amount of lemonade remains constant at 6 gallons, which represents 2 parts, one part equals 3 gallons. The new mixture requires 5 parts of water, which amounts to 15 gallons. Subtracting the 3 gallons of water already present shows that 12 gallons of water must be added.

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