Multiple choice

Container 'A' contains milk and water in the ratio of 4 : 1. Container 'B' has the same mixture in the ratio of 3 : 1. What minimum quantity of mixture in container 'A' should to be added to 10 litres of mixture in container 'B' to get a resultant milk concentration of atleast 78%?

  1. 8 litres

  2. 10 litres

  3. 12 litres

  4. 15 litres

  5. 20 litres
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Container B has 7.5 litres of milk in 10 litres of mixture. If x litres from A are added, the milk amount is 7.5 + 0.8x, and the total volume is 10 + x. Solving 7.5 + 0.8x >= 0.78(10 + x) gives x >= 15 litres.

AI explanation

Container A has a milk concentration of 80%, while container B has a concentration of 75%. Mixing 10 liters of B with x liters of A requires the equation 10 multiplied by 0.75 plus x multiplied by 0.80 to be greater than or equal to 0.78 multiplied by the sum of 10 and x. This simplifies to 7.5 plus 0.8x being at least 7.8 plus 0.78x. Solving yields x at least 15, so 15 liters is the minimum required.

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