Multiple choice

A black jute bag contains 'L' kg of red lentils. In order to make a mixture of pulses, he takes out 30 kg of red lentils from the black bag and adds 20 kg of Bengal grams in the black bag after which the ratio of Red lentils to Bengal grams in the bag becomes 3 : 2. If another white jute bag contains Red lentils 'G' kg more than that in the black bag initially and if 25 kg of Bengal grams is added, then the ratio of Red lentils to Bengal grams becomes 4 : 1. Find the value of G.

  1. 45

  2. 50

  3. 40

  4. 30

  5. 35

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Black bag: (L-30)/20 = 3/2 => 2L-60 = 60 => L=60. White bag: (L+G)/25 = 4/1 => 60+G = 100 => G=40.

AI explanation

After taking out 30 kg of red lentils and adding 20 kg of Bengal grams, the black bag holds (L - 30) kg of red lentils and 20 kg of Bengal grams, establishing the ratio (L - 30) / 20 = 3 / 2, which solves to L = 60 kg. The white bag initially holds 60 + G kg of red lentils, and adding 25 kg of Bengal grams gives the ratio (60 + G) / 25 = 4 / 1. Solving this second equation gives 60 + G = 100, making the value of G equal to 40.