Multiple choice

In a 250 liter of a mixture of Milk and Water, Water is X%. The milkman sold 50 litters of the mixture and replaced same quantity with water. If the percent of Milk in final mixture is 64%, then what is the percentage of Milk in the initial mixture?

  1. 20%

  2. 40%

  3. 60%

  4. 80%

  5. 50%
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Initial: 250L, Milk = (100-X)%, Water = X%. Sold 50L, remaining 200L. Replaced 50L with water. Total 250L. Final Milk % = 64%. Amount of milk = 250 * 0.64 = 160L. The 50L removed contained (100-X)% milk. So 250 * (100-X)/100 - 50 * (100-X)/100 = 160. 200 * (100-X)/100 = 160. 2 * (100-X) = 160. 100-X = 80. X = 20. Initial milk = 100-20 = 80%.

AI explanation

Since the final mixture is 64% milk, the amount of milk after replacing 50 liters with water is 64% of 250, or 160 liters. Because 50 liters were removed, the 200 liters of remaining original mixture contains this 160 liters of milk, meaning the original mixture had a milk concentration of 80%. The initial percentage of milk in the 250-liter mixture was 80%.

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