The area of the circle whose centre is (1, 2) and passes through (4, 6) is
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The area of the circle whose centre is (1, 2) and passes through (4, 6) is
5 π
10 π
25 π
36 π
44 π
Radius squared = (4-1)^2 + (6-2)^2 = 3^2 + 4^2 = 9 + 16 = 25. Area = pi * r^2 = 25 * pi.
To find the radius of the circle, use the distance formula between the center (1, 2) and the point on the circumference (4, 6), which is the square root of the quantity (4 minus 1) squared plus (6 minus 2) squared. This calculation gives the square root of 9 plus 16, resulting in a radius of 5. The area of the circle is then found using the formula pi times the radius squared, yielding an area of 25 pi.