The area of the circle whose centre is (3, 4) and passes through (6, 8), is
Reveal answer
Fill a bubble to check yourself
The area of the circle whose centre is (3, 4) and passes through (6, 8), is
5π sq. units
10π sq. units
25π sq. units
36π sq. units
15π sq. units
Radius^2 = (6-3)^2 + (8-4)^2 = 3^2 + 4^2 = 9 + 16 = 25. Area = pi * r^2 = 25 * pi.
Using the distance formula, the radius r is the distance between (3, 4) and (6, 8), which is calculated as the square root of (6 minus 3) squared plus (8 minus 4) squared. This gives the square root of 9 plus 16, resulting in a radius of 5 units. Applying the area of a circle formula, area equals pi times r squared, the area is pi times 5 squared, which equals 25 pi square units.