Multiple choice

In a school lab, a student took 20 ml of a solution that contained 20% volume sulphuric acid. To dilute it, he added water to the solution to 3% strength. Find the amount of water added.

  1. 113.33 ml

  2. 115.53 ml

  3. 116.85 ml

  4. 119.12 ml

  5. None of these
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A Correct answer
Explanation

The amount of acid remains constant during dilution. Initially, there is 20 ml * 0.20 = 4 ml of acid. After adding water, the total volume V satisfies 4 / V = 0.03, so V = 4 / 0.03 = 133.33 ml. The amount of water added is 133.33 ml - 20 ml = 113.33 ml.

AI explanation

The initial 20 ml solution contains 20% sulphuric acid, meaning it has 4 ml of acid, and the acid volume remains constant when water is added. To achieve a 3% strength, the total volume of the diluted solution must be 4 ml divided by 0.03, which equals 1133.33 ml. The amount of water added is the final volume minus the initial volume, giving 1133.33 ml minus 20 ml, which is approximately 113.33 ml.

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