A barrel contains mixture of spirit and kerosene in the ratio 8 : 5. When 91 litres of mixture is used from barrel and again refilled with kerosene only, then the ratio becomes 8 : 9. Calculate the quantity of spirit present in the barrel before use.
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238 litres
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280 litres
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300 litres
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340 litres
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None of these
A
Correct answer
Explanation
Let initial spirit be 8x and kerosene be 5x. Total = 13x. Removed 91 litres, so removed (8/13)*91 = 56 spirit and (5/13)*91 = 35 kerosene. Remaining: 8x - 56 spirit, 5x - 35 + 91 kerosene. New ratio: (8x - 56) / (5x + 56) = 8/9. 72x - 504 = 40x + 448 => 32x = 952 => x = 29.75. Initial spirit = 8 * 29.75 = 238.