Multiple choice

A dishonest milkman fills up his bucket which is only 4/5 full of milk, with water. He removes 5 litres of the mixture from the bucket and adds equal quantity of water. If the mixture now contains 60% of milk. What is the capacity of the bucket in litres?

  1. 15

  2. 20

  3. 25

  4. 30

  5. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let capacity be C. Initial milk = 4/5 * C. Removing 5L of mixture removes 5 * (4/5) = 4L of milk. Adding 5L water keeps volume C. Final milk = (4/5 * C - 4) / C = 0.6. 0.8C - 4 = 0.6C => 0.2C = 4 => C = 20.

AI explanation

Let the capacity of the bucket be V, where the initial milk volume is 4V divided by 5. Using the replacement formula, the final quantity of milk is (4V divided by 5) multiplied by (1 minus 5 divided by V), which equals 0.60V. Solving the equation (4V divided by 5) multiplied by (V minus 5) divided by V equals 3V divided by 5 gives 4V minus 20 equals 3V, so the capacity V is 20 litres.

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