Multiple choice

36 L of pure water is added to a container containing 160 L of pure alcohol. 98 L of the resultant mixture was taken out and some more quantities of pure alcohol and pure water were added to the container in the ratio 2 : 1. What was the quantity of pure alcohol added to the container, if the resultant ratio of alcohol and water in the container is 4 : 1?

  1. 2 L

  2. 4 L

  3. 6 L

  4. 8 L

  5. 10 L
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Initial: 160A, 36W. Total 196. Remove 98L (half the mixture). Remaining: 80A, 18W. Add x alcohol and x/2 water. Result: (80+x)/(18+x/2) = 4/1. 80+x = 72 + 2x. x = 8.

AI explanation

The initial mixture combines 160 L of alcohol and 36 L of water to make 196 L; removing 98 L of this mixture leaves exactly 80 L of alcohol and 18 L of water. Let the quantity of pure alcohol and pure water added be 2x and x respectively, making the new amounts (80 + 2x) and (18 + x). Using the given final ratio of 4 to 1, the equation is (80 + 2x) divided by (18 + x) equals 4, which solves to x = 4. Since the added alcohol is 2x, the quantity of pure alcohol added is 8 L.

Keep practicing — related questions