What is the farthest distance between two points on a cylinder of height 8 and radius 8?
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What is the farthest distance between two points on a cylinder of height 8 and radius 8?
8 5
8 2
16 5
8 3
The greatest distance is between opposite points on the two circular rims. The horizontal separation is 2r = 16 and the vertical separation is 8, giving distance sqrt(16^2 + 8^2) = 8sqrt(5).
The farthest distance between two points on a cylinder is the length of the diagonal across the cylinder, found using the Pythagorean theorem with the diameter and the height. The diameter is twice the radius, giving a diameter of 2 * 8 = 16. Using the Pythagorean theorem, the distance is the square root of the sum of the squares of the height and the diameter: sqrt(8^2 + 16^2) = sqrt(64 + 256) = sqrt(320). Simplifying the square root gives sqrt(64 * 5) = 8 sqrt(5).