Multiple choice

A solid spherical ball weighing 2 kg, when immersed in a cylinder of base radius 12 cm, raises the level of water in the cylinder by 2 cm. Find the radius of the ball in cm. (Assume density of water as 1000 kg/m3)

  1. 3

  2. 6

  3. 9

  4. 12
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Volume of water displaced = pi * r^2 * h = pi * 12^2 * 2 = 288 * pi. Volume of sphere = 4/3 * pi * R^3. 288 * pi = 4/3 * pi * R^3 -> R^3 = 288 * 3 / 4 = 216. R = 6.

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