A bucket contains 200 cc of liquid. A solid ball is dropped in the bucket resulting in the rise of liquid level to 1.3 times of its original level. If the radius of the base of the bucket is 3 cm and the radius of the surface of the liquid level is 1 cm more than the radius of the base of the bucket before the ball is dropped, find the volume of the solid metal ball.

The new liquid volume is 1.3 times the original volume of 200 cc, which equals 260 cc. The volume of the solid ball is the difference between the new and original volumes, so 260 cc minus 200 cc equals 80 cc. The radius information is extra data not needed for this calculation. The volume of the solid metal ball is 80 cc.

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