A right circular cylinder has height 28 cm and radius of base 14 cm. Two hemispheres of radius 7 cm each are cut from each of the two bases of the cylinder. What is the total surface area (in cm²) of the remaining part?

The total surface area of the remaining part equals the total surface area of the cylinder plus the curved surface areas of the two hemispheres. The cylinder's surface area is 2 * pi * 14 * (14 + 28) = 3696. The curved surface area of the two hemispheres is 2 * (2 * pi * 7^2) = 616. The combined total surface area is 3696 + 616 = 4312 sq cm.

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