Multiple choice

A cylinder has a base radius of 2 and a height of 9. To the nearest whole number, by how much does the lateral area exceed the sum of the areas of the two bases?

  1. 101

  2. 96

  3. 88

  4. 81

  5. 75

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Lateral area = 2*pi*r*h = 2*pi*2*9 = 36*pi. Sum of base areas = 2*pi*r^2 = 2*pi*4 = 8*pi. Difference = 28*pi. Using pi=3.14, 28*3.14 = 87.92, which rounds to 88.

AI explanation

The lateral surface area of a cylinder is 2 h and the combined area of the two bases is 2 r^2, so the difference is 2 h - 2 r^2. Plugging in radius 2 and height 9 gives 2(2)(9) - 2 (2^2) = 36 - 8 = 28 . Using the approximation 3.14 for gives 87.92, which rounds to the nearest whole number of 88.