Multiple choice

What is the probability that at least one 6 appears when 3 dice are thrown?

  1. 125 216

  2. 1 36

  3. 91 216

  4. 92 216
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C Correct answer
Explanation

Probability of no 6 in one throw = 5/6. Probability of no 6 in 3 throws = (5/6)^3 = 125/216. Probability of at least one 6 = 1 - 125/216 = 91/216.

AI explanation

When three dice are thrown, the total number of outcomes is 216. The probability of getting at least one six is calculated by subtracting the probability of getting no sixes from one. The number of outcomes with no sixes is 5 multiplied by 5 multiplied by 5, which is 125. Therefore, the required probability is 1 minus 125 divided by 216, which equals 91 divided by 216.

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