Multiple choice

A die is thrown twice. What is the probability that at least one of the two dice shows the number 4?

  1. 1 3

  2. 11 36

  3. 1 4

  4. 5 18
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B Correct answer
Explanation

The probability that neither throw shows 4 is (5/6)^2 = 25/36. Therefore, the probability of at least one 4 is 1 - 25/36 = 11/36.

AI explanation

The total number of outcomes when a die is thrown twice is 36. The probability of at least one four is found by subtracting the probability of neither die showing a four, which is 25 out of 36, from one. This gives 1 minus 25 divided by 36, yielding 11 divided by 36.

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