Each of two persons tosses three fair coins. The probability that they obtain the same number of heads, is
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Each of two persons tosses three fair coins. The probability that they obtain the same number of heads, is
1/2
5/16
7/16
none of these
Each person tosses 3 coins. The probability distribution for heads is: 0 heads (1/8), 1 head (3/8), 2 heads (3/8), 3 heads (1/8). The probability they get the same number of heads is the sum of the squares of these probabilities: (1/8)^2 + (3/8)^2 + (3/8)^2 + (1/8)^2 = (1 + 9 + 9 + 1) / 64 = 20 / 64 = 5/16.
Using the binomial distribution, the probability of getting k heads for each person is found by combining the probabilities that both obtain exactly k heads. The probabilities for obtaining zero, one, two, and three heads are 1/8, 3/8, 3/8, and 1/8, respectively. We square each probability and sum the results: (1/8)^2 + (3/8)^2 + (3/8)^2 + (1/8)^2 = 1/64 + 9/64 + 9/64 + 1/64 = 20/64 = 5/16. The probability they obtain the same number of heads is 5/16.